The graph of a linear system is shown.

What is the solution to this linear system? Enter a value in each box to create an ordered pair.

( , )

Answer:

The length of the wire is 3.24451394 × 10⁻⁹ cm

Step-by-step explanation:

The volume of the wire = 66 cm³

The diameter of the wire = 1 mile

We convert the volume from cm³ into mile³  to get;

66 cm³ = 1.5834 × 10⁻¹⁴ mile³

The volume = π × D²/4 × l

Where;

D = The diameter = 1 mile

l = The length of the wire

1.5834 × 10⁻¹⁴ = π × 1²/4 × l

The length of the wire = l = 1.5834 × 10⁻¹⁴/(π × 1²/4) = 2.0160475 × 10⁻¹⁴ mile

1 mile = 160,934.4 cm

2.0160475 × 10⁻¹⁴ mile = 2.0160475 × 10⁻¹⁴ × 160,934.4 cm = 3.24451394 × 10⁻⁹ cm  

The length of the wire = 3.24451394 × 10⁻⁹ cm

Answer:

I believe it is 40% since there are 4 marbles within the bag!

Step-by-step explanation:

Answer:

Step-by-step explanation:

AP formula:

Using the given points we find the common difference:

a₁ = -22 and a₈ = 5

Now the missing terms:

Answer:

BI=BK

Step-by-step explanation:

BJ=BJ(common side)

<BJI=<BJK=90° (Perpendicular given)

IJ=JK (Bisector given)

congruent triangle ∆BIJ=~∆BKJ (RHS rule)

therefore, BI= BK

Answer:

x=-3

Step-by-step explanation:

Step-by-step explanation:

-3x=9

x= -3 Hope this helps

Answer:

.56

Step-by-step explanation:

Use a calculator.

Answer:

64

Step-by-step explanation:

1st step: 36/9 = 4

54 - 4 + 14  (since all operations are addition and subtraction, just work left to right)

50 + 14 = 64

Answer:

5

Step-by-step explanation:

hope this helps :)

5^2=25

5x5=25

Answer:

1. 7 people play soccer

2. 5 people play ONLY soccer.

3. 2 people play both soccer and basketball

Step-by-step explanation:

One side of the venn diagram is Basketball.

the other side is soccer.

the middle is both.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

Answer:

The slope is -0.25. This means that the power reduces by 0.25 percent per hour

Step-by-step explanation:

Given

[tex]y = -0.25x + 1[/tex]

Required

Identify and interpret the slope

An equation has a general form:

[tex]y = mx + b[/tex]

Where

[tex]m = slope[/tex]

Compare [tex]y = mx + b[/tex] to [tex]y = -0.25x + 1[/tex]

We have:

[tex]mx = -0.25x[/tex]

Divide both sides by x

[tex]\frac{mx}{x} = \frac{-0.25x}{x}[/tex]

[tex]m = \frac{-0.25x}{x}[/tex]

[tex]m = -0.25[/tex]

Because the result of the above calculation is negative, it means that the function reduces

The given function measures the percentage of power by hour.

So, the power reduces by 0.25% per hour

Answer: depends on the task.

Step-by-step explanation: If it is one where it is for an important person, make anyone available do it. If it's very complicated, get your smartest person do it. Not very complicated, ask for anyone who is up for the job.

Answer:

[tex]2d^{\frac{7}{10}}[/tex] [tex]= \sqrt[10]{2d^7}[/tex]

Step-by-step explanation:

Given

[tex]2d^{\frac{7}{10}}[/tex]

Required

Determine the radical expression

To do this, we apply the following law of indices:

[tex]a^{\frac{m}{n}} = \sqrt[n]{a^m}[/tex]

By comparing the above to [tex]2d^{\frac{7}{10}}[/tex], we have:

[tex]m=7[/tex]

[tex]n = 10[/tex]

So, the solution becomes

[tex]2d^{\frac{7}{10}}[/tex] [tex]= \sqrt[10]{2d^7}[/tex]

Answer:

khkatyyjajtzjyftkrtehemrk5u2w

Answer:

Step-by-step explanation:

here you go mate'

step 1

(60 + 10)130  equation

step 2

(60 + 10)130  simplify with the brackets

step 3

130(70)  multiply the numbers

answer

9100

Answer: It's (A) 12<X

Step-by-step explanation: I chose that one because the line highlighted on the number line, it's bigger than 12!

Answer:  In the custom setting, choose the ‘My Object’ option in the material drop down box.  Set the mass of your object to 4 kg.  Adjust the volume to find the minimum volume needed to make the object float.

   Volume________4.09_L________                Density__________.98 kg/L________

      2.      How does the density of a large piece of aluminum compare to a small piece?

Step-by-step explanation:

Answer:

The area of one rectangle is 15 cm²

Step-by-step explanation:

The given parameters are;

The area of the square = 64 cm²

The length of the rectangles = 5 cm

The formula for the area of a square = (Side length)² = S²

Therefore, whereby the side length of the given square = S, we have;

Area of the square = 64 = S × S = S²

S = √(64 cm²) = 8 cm

The side length of the square = 8 cm

The perimeter of a square = The length of the string = Side length × 4 = 8 cm × 4 = 32 cm

∴ The perimeter of a square = The length of the string = 32 cm

The length of the string = The perimeter of the two congruent rectangle = 32 cm

Therefore;

The perimeter of each rectangle = 32/2 cm = 16 cm

Given that the length, L of the side of each rectangle is L = 5 cm, we have;

The perimeter of a rectangle = 2 × L + 2 × W

Where;

W = The width

The perimeter of the rectangle = 16 = 2 × 5 + 2 × W

2 × W = 16 - 2 × 5 = 6

W = 6/2 = 3

W = 3 cm

The width, W, of each rectangle is W = 3 cm

The area of one rectangle = W × L = 3 cm × 5 cm = 15 cm²

The area of one rectangle = 15 cm².

Answer:

C. 24

Step-by-step explanation:

Answer:

250*2.38= 595. so the answer is 595

Answer:

0.47 miles per hour

Step-by-step explanation:

Answer:

13.00 ; 7.00

Step-by-step explanation:

The decimal equivalent of :

2 + 11 = 13 ; expressed as a float = 13.00

The decimal equivalent of :

4 + 3 = 7 ; expressed as a floating point number = 7.00

From the description of the construction of the congruent angle, we have;

The statement that describes step 3 correctly is; Use the same width of the compass to draw an arc from point N that intersects the segment AN at a point X

The reason for making the above selection is as follows:

The steps to construct an angle congruent to another angle are;

Step 1: Given an angle PQR, draw a working segment NT

Step 2: Place the needle of the compass at point Q and draw an arc (Q, QA), intersecting sides PQ and QR of the angle ∠PQR at points A and B respectively

Step 3: Place the needle of the compass at point N and draw an arc with the compass width QA from above the to intersect the segment NT at a point X

Step 4: Set the compass width to the distance AB with which an arc is drawn from point X so as to intersect the arc (N, QA) above at point Y

Step 5: The points Y and N are joined with a straight line to form the congruent angle

Analysis of the steps:

Given that in step 4, we have that the the arc drawn from point X with compass width AB is meant to intersect the arc drawn from point N, at point Y, we have that in step 3 an arc was drawn from point N with compass width QA from step 2 to intersect NT at a point X

Therefore;

Step 3 is best described by the following statement;

Use the same width of the compass to draw an arc from point N that intersects the segment AN at a point X

Learn more about the construction of congruent angles here:

https://brainly.com/question/9781303

Use the same width of the compass to draw an arc from point N that intersects the segment NT at a point X.

This option gives us the step 3.

This is because we want to have equal angles. Therefore we select an arc equal in length to arc AB which intersects NT at  point X.

This can be explained more with the help of a diagram.

Two angles are equal when their dimensions are equal.

Arcs of equal length would give congruent angles.

https://brainly.com/question/11406334

Answer:

5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

8x - 6 > 12 + 2x

Step 2: Solve for x

Here we see that any value x greater than 3 would work as a solution to the inequality.

Out of the answer choices, 5 is the only number greater than 3.

By the remainder theorem, if p(x) = x³ - 3x² + kx - 1 and x - 1 is a factor p(x), then the remainder upon dividing p(x) by x - 1 is p (1) = 0.

So we have

p (1) = 1³ - 3 • 1² + k - 1 = 0

Solve for k :

1 - 3 + k - 1 = 0

k = 3

Answer: 40%

Steps are below

Step-by-step explanation:

First, let's find the amount of salt. 160/100=1.6, then 1.6x35 is 56. So the current amount of salt before we add more salt is 56g. Now that we know the amount of salt, let's find the amount of water. The total amount of solution is 160g, 56g of that is salt, and the rest is pure water. 160-56= 104g of pure water. Let's add 24 grams of salt and 16 grams of pure water. We now have 80g of salt, and 120g of water. A common mistake is doing 80/120, WHICH IS INCORRECT. The correct formula for solution/concentration is the amount of substance/total amount of solution. So you'd do 80+120 to get 200, and then do 80/200 which gets you 40%.

Hope it helps!! :D

Answer:

See Below.

Step-by-step explanation:

We are given a point P(x, y). It is equidistant from A(3, 6) and B(-3, 4).

So, let's first determine the distance from P to each point. We can use the distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Segment PA:

We will let P(x, y) be (x₂, y₂) and A(3, 6) be (x₁, y₁). By substitution:

[tex]d=\sqrt{(x-3)^2+(y-6)^2[/tex]

This represents the distance from P to A.

Segment PB:

Again, we will let P(x, y) be (x₂, y₂) and B(-3, 4) be (x₁, y₁). By the distance formula:

[tex]d=\sqrt{(x-(-3))^2+(y-4)^2}[/tex]

We may simplify:

[tex]d=\sqrt{(x+3)^2+(y-4)^2}[/tex]

Now, we know that the two distances are equivalent. Hence:

[tex]\sqrt{(x-3)^2+(y-6)^2}=\sqrt{(x+3)^2+(y-4)^2[/tex]

Simplify. Square both sides:

[tex](x-3)^2+(y-6)^2=(x+3)^2+(y-4)^2[/tex]

Square:

[tex](x^2-6x+9)+(y^2-12x+36)=(x^2+6x+9)+(y^2-8x+16)[/tex]

Subtract all terms from the right:

[tex](x^2-6x+9)-(x^2+6x+9)+(y^2-12x+36)-(y^2-8x+16)=0[/tex]

Distribute the negative:

[tex][(x^2-6x+9)+(-x^2-6x-9)]+[(y^2-12y+36)+(-y^2+8y-16)]=0[/tex]

Rearrange:

[tex][(x^2-x^2)+(-6x-6x)+(9-9)]+[(y^2-y^2)+(-12y+8y)+(36-16)]=0[/tex]

Combine like terms;

[tex](-12x)+(-4y)+(20)=0[/tex]

We can divide both sides by -4:

[tex]3x+y-5=0[/tex]

Finally, adding 5 to both sides produces:

[tex]3x+y=5[/tex]

Answer:

B.4

Step-by-step explanation:

It's asking the absolute value even though -6 is used here. So the answer is 4.

Answer:

3

Examples of Everyday Radiation

Visible light.

Infrared light.

Near ultraviolet light.

Microwaves.

Low frequency waves.

Radio waves.

Waves produced by mobile phones.

A campfire's heat.