Some of Mr. Edward's students want to buy him a gift. If each of
them pays $2, they will be short of $4 for the gift. If each of them
pays $3, there will be an extra $3. How much does the gift cost?

The probability of picking a golfball then a basketball is 7/200

The probability of picking two baseballs is 3/20.

The probability of picking a baseball then a football is 1/12.

The probability of picking two footballs is 1/30

Probability is used to calculate the likelihood of an event happening. The odds the event occurs is 1 and the probability that the event does not occur is 0.

The probability of picking a golfball then a basketball = 7/25 x 3/24 = 7/200

The probability of picking two baseballs = 10/25 x 9/24 =18/120 = 3/20

The probability of picking a baseball then a football = 10/25 x 5/24 = 1/12

The probability of picking two footballs = 5/25 x 4/24 = 1/30

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The derivative of h(x) in A is 2x+24

h'(x)=0 g'(x)=0

2x+24=0 2x=0

x=-12 x=0

Similarly the derivative of h(x) in D is 2x-24

h'(x)=0 g'(x)=0

x=12 x=0

We know that the only difference comes down to the y-value when substituting x=0 in h(x).

The y-value of the vertex of h(x) must be +12 the y-value of the vertex of g(x).

We have to add 12 to get to the x-value, which means that the third option or C is your answer.

Answer:

The Third table down is the answer, as it has a consistant rate of change for both X and Y

Answer:

The Answer is C.

Step-by-step explanation:

By looking at the y-axis we can see if they go up by the values by down by 8.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's calculate the Given terms ~

[tex] \textbf{1st Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 8 - 5(1)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 8 - 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_1 = 3[/tex]

[tex] \textbf{2nd Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = 8 - 5(2)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = 8 - 10[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_2 = - 2[/tex]

[tex] \textbf{3rd Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = 8 - 5(3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = 8 - 15[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_3 = - 7[/tex]

[tex] \textbf{4th Term : } [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = 8 - 5(4)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = 8 -20[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_4 = - 12[/tex]

[tex] \textbf{5th Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = 8 - 5(5)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = 8 - 25[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_5 = -17[/tex]

[tex] \textbf{10th Term :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = 8 - 5(10)[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = 8 - 50[/tex]

[tex]\qquad \sf  \dashrightarrow \:a_{10} = - 42[/tex]

#1

#2

#3

#4

#5

#10

complementary angles have sum 90°

m<A

Answer:33

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

B   there is two values of y for x = 3.5     so ....not a function

The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.

The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.

Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)

For the angular velocity at time period (t = 3s), we have:

ω = 2π/T

ω = 2π/3

Mathematically, the standard equation of a cosine function is given by:

y = Acos(ω)t

Substituting the given parameters into the formula, we have;

d = -9cos(2π/3)t.

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Answer:

B.    d =    -9cos ( 2 pi/3 t)

Step-by-step explanation:

Have a good day

Answer:

The scale drawing is 1 centimeter to 50 meters  ⇒ answer E

Step-By-Step Explanation:

* Lets explain how to solve the problem

- The height of the empire state building is about 1450 feet long and

 400 feet wide

- Andre wants to make a scale drawing of the front view of it on an

8 1/2 inches by 11 inches piece of paper

- We need to select one of these scales that we think is the most

appropriate for the scale drawing

A. 1 inch to 1 foot

B. 1 inch to 100 feet

C. 1 inch to 1 mile

D. 1 centimeter to 1 meter

E. 1 centimeter to 50 meters

F. 1 centimeter to 1 kilometer

- For scale A , B , and D the scaled image will not fit the page

- For scale C and F the drawing will be very small because 1 mile

is 5280 feet and 1 kilometer is 3280.84 feet

- E is most appropriate because 1 meter is 3.28084 feet, then the

height of the empire state is 442 m dividing by 50 m gives about

8.8 cm and the height of the paper is 11 inches which is about 28 cm

and the width of the empire state is about 122 m dividing by 50 m

gives about 2.5 cm and the width of the paper is 8 1/2 inches which

is about 22 cm then the drawing will be appropriate for drawing

∴ The scale drawing is 1 centimeter to 50 meters

Answer:

y = 3x + 15

Step-by-step explanation:

1. Find the reciprocal of the slope and change signs: -3

2. y = 3x + b

3. Plug in x and y --> b = 15

4. Make your equation using y = mx + b: y = 3x + 15

The equation of the perpendicular line 't' will be equal to y = -3x + 3.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given that line, s has an equation of y=1/3-X-5. Line t is perpendicular to line 's' and passes through (-2, 9).

The equation of the line will be calculated as,

For the perpendicular line, the slope is reciprocal with a negative sign,

m = -3

The equation of the line will be written as,

y = mx + c

y = -3x + c

9 = ( -3 x - 2) +c

c = 9 - 6

c = 3

The equation is,

y = mx + c

y = -3x + 3

Therefore, the equation of the perpendicular line 't' will be equal to y = -3x + 3.

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Answer:

Answer is B.

Step-by-step explanation:

Domain: All real numbers except -6

Set denomator of x + 6 = 0

x + 6  = 0

x ≠ -6

If we plug in x = -6 into the equation we get 4/0 making it undefined. So exclude x = -6 on domain.

Range: All real numbers except 0

y ≠ 0

Answer:

The period is the change in x required for the function to return to the same value, changing in the same direction. The first two table entries are v(x) = 41.7 and 35.7. The next time that sequence appears is when x=44, so the period is ...

 period = 44 -4 = 40 . . . seconds

__

The minimum table value is 20; the maximum is 44, so the midline of the function is their average:

 midline = (20 +44)/2 = 32

__

The amplitude is the maximum deviation from the midline, so is ...

 amplitude = 44 -32 = 12

Step-by-step explanation:

Step-by-step explanation:

1/100 .................

Answer:

f ( x ) = sin ( x )

Step-by-step explanation:

Answer:

that is a f(X)=sin(x) curve

Step-by-step explanation:

the curve cuts the origin as it moves upwards and has the same amplitude

Answer:

Markdown

Step-by-step explanation:

For example: the price of the shirt was $10.00 It had a markdown of 15%. This would be $8.5.

Answer:

the fourth anwser

markdown

Answer:

Don't worry, we all over sleep sometimes. This is quiet simple. So you need to find x. 12 went from 12, to 4. So 12/_=4 The __ would be 3.
x on the other hand should be 3 as well. I could be wrong. But 12/3=4. So that'd be 12/3 Then it would be 4/3.

Step-by-step explanation:

X=3. I could be wrong.

1/3 is a proper fraction

hope it helps...!!!

We get that statements 2 and 3 are correct statements.

We have given that the

6>-2

We have to find the correct statement from the given statement,

Less than or equal to relation is one of the inequalities used to represent the relation between two non-equal numbers or other mathematical expressions.

1) 6/2<2/-2

3<-1

This is not possible therefore first statement is not correct

2) 6/-2<-2/-2

-6<1

This is the correct statement.

3)

6/2<-2/2

3<-1

This is the correct condition.

Therefore this is a correct statement.

Therefore we get that statements 2 and 3 are a correct statements.

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Answer:

A D F

Step-by-step explanation:

dont waste your time :)

Answer:

1. Mean is 14.5  Median is 13.5   Mode is 13

2. Mean is 84  Median is 84  Mode is 84

3. Mean is 26.6 Median is 27 Mode is 20

4. Mean is 87   Median is 87 Mode is 87

5. Mean is 14.6 Median is 14 Mode is 14,12

Step-by-step explanation:

Hope this helps!! May not be entirely right but tried to do it quick for you

Answer:

A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

Step-by-step explanation:

Step 1:  Determine the sides

A → 3 ft

B → 7 ft

C → 4 ft

D → 5 ft

Step 2:  Determine the surface area

Area of the sides

[tex]A= 4\ ft * 7\ ft = 28\ ft^2[/tex]

[tex]A= 5\ ft * 7\ ft = 35\ ft^2[/tex]

[tex]A= 3\ ft * 7\ ft = 21\ ft^2[/tex]

Area of the top and bottom triangles

[tex]A= \frac{h\ *\ b}{2} = \frac{3\ ft\ *\ 4\ ft}{2} = \frac{12\ ft^2}{2} = 6\ ft^2 = 2(6\ ft^2) = 12\ ft^2[/tex]

Total Area

[tex]28\ ft^2 + 35\ ft^2 + 21\ ft^2 + 12\ ft^2[/tex]

[tex]96\ ft^2[/tex]

Answer:  A = 3 ft, B = 7 ft, C = 4 ft, D = 5 ft, Surface Area = 96 ft^2

Answer:

Surface Area = 96 ft^2

Step-by-step explanation:

A = 3 ft.

B = 7 ft.

C = 4 ft.

D = 5 ft.

Surface Area:

Triangle: Area = 1/2 * Base * Height

Top Triangle: Area = 1/2 * 4 * 3 = 1/2 * 12 = 6 ft^2

Bottom Triangle: Area = 6 ft^2

Rectangle: Area = Length * Width

Left Rectangle: Area = 7 * 4 = 28 ft^2

Mid Rectangle: Area = 7 * 5 = 35 ft^2

Right Rectangle: Area = 7 * 3 = 21 ft^2

Surface Area = TopTri + BotTri + LeftRect + MidRect + RightRect

Surface Area = 6 + 6 + 28 + 35 + 21 = 96 ft^2

Answer:

Andy made the error of adding the values of the bags and the ballons, when instead they should be multiplied. The total number of baloons Mrs. Ruiz bought is 350 because 70*5 is 350. You multiple because there are five bags and in each of the five bags, there are 70 balloons.

An interval can be defined as a set of real numbers. The interval (44-47), (48-51), and (56-59) will have frequencies of 3, 4, and 1.

A collection of real numbers between two specified values known as the interval's endpoints is referred to as an interval.

The data set given to us is 42, 43, 46, 47, 47, 48, 49, 50, 51, 53, 55, 55, 59. Therefore, the frequency can be written as,

Thus, the interval (44-47), (48-51), and (56-59) will have frequencies of 3, 4, and 1.

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Answer:

3 4 1

Step-by-step explanation:

I took the assignment and got it right

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

The equation of a circle of center [tex](x_0, y_0)[/tex] and radius r is given by:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

In this problem, the circle is centered at the origin, hence [tex](x_0, y_0) = (0,0)[/tex].

The circle contains the point (-13,0), hence the radius is found as follows:

[tex]x^2 + y^2 = r^2[/tex]

[tex](-13)^2 + 0^2 = t^2[/tex]

[tex]r^2 = 169[/tex]

Hence the equation is:

[tex]x^2 + y^2 = 169[/tex]

Then, we test if point (√5, 12) is on the circle:

[tex]x^2 + y^2 = 169[/tex]

[tex](\sqrt{5})^2 + 12^2 = 169[/tex]

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

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Answer:

(9,-15)

Step-by-step explanation:

( 5 - (-4), -8 -7 )

( 9 , -15)

I hope my answer helps you.

Answer:

(-9,15)

Step-by-step explanation:

v-u = ((-4-5),(7-(-8)))

= (-9,(7+8))

= (-9,15)

Answer:

The slope is [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

Hi there!

We are given the points (0, 4) and (6, 13)

We want to find the slope of the line containing these two points

Slope (m) is the steepness of the line. When calculating from two points, you use the equation [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are points

Although we have what we need to find the slope, let's label the values of the points to avoid confusion and mistakes.

[tex]x_1=0\\y_1=4\\x_2=6\\y_2=13[/tex]

Substitute these values into the equation

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{13-4}{6-0}[/tex]

Subtract

m=[tex]\frac{9}{6}[/tex]

Simplify

m=[tex]\frac{3}{2}[/tex]

The slope of the line is 3/2

Hope this helps!

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