NEED ANSWER FAST PLEASE HELP!!!
If y − 4 = 2x, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
A. {(2, 1), (4, 2), (6, 3)}
B. {(1, 2), (2, 4), (3, 6)}
C. {(4, 0), (6, 1), (8, 2)}
D. {(0, 4), (1, 6), (2, 8)}
Answer:
D
Step-by-step explanation:
plug in the coordinates for x and y
Find the distance between the points (2,8) and (17,0).
Answer:
[tex]d = 17[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra II
Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Point (2, 8)
Point (17, 0)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d.
Substitute [DF]: [tex]d = \sqrt{(17-2)^2+(0-8)^2}[/tex]Subtract: [tex]d = \sqrt{(15)^2+(-8)^2}[/tex]Exponents: [tex]d = \sqrt{225+64}[/tex]Add: [tex]d = \sqrt{289}[/tex]Simplify: [tex]d = 17[/tex]I need help!! Given: Quadrilateral pqrt , qsv , ptv , qv bisects rt , and Qr//pv
prove: QS=VS
What is the Statement and Reasons
Answer:
Statement 1: Quadrilateral PQRT; line QSV; line PTV line QV bisects line RT, and line OR is parallel to line PV
Statement 3: angle QSR is congruent to angle VST
Statement 5: Triangle RSQ is congruent to angle TSV
Reason 1: Given
Reason 2: If a line bisects a segment, then it divides the segment into two congruent segments.
Reason 4: If two lines are parallel, then the alternate interior angles are congruent.
Step-by-step explanation:
The first statement will always be your given statements.
The given result is proved by ASA congruence criteria.
What are the criteria for congruent triangles?Two triangles are said to be congruent when all of their corresponding sides and angles are equal. For this relation between two triangles, there are many criteria such as SSS, SAS, ASA and RHS.
The given problem can be solved in statement and reason form as follows,
In triangles ΔQSR and ΔTSV,
Statement Reason
1. ∠QRS = ∠STV Alternate interior angles for QR║PV
2. RS = TS QV bisects Line segment RT
3. ∠QRS = ∠VTS Vertically opposite angles
4. ΔQSR ≅ ΔTSV Triangles are congruent by ASA
Thus, QS =VS due to corresponding parts of congruent triangles.
Hence, QS = VS is proved by the ASA criteria for congruent triangles.
To know more about congruent triangles click on,
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Which of the following is the equation of the line that is perpendicular to y=-4x-5 and goes through the point (-2, 3)? Question 14 options: y=-4x-5 y=-1/4x+5/2 y=1/4x+7/2 y=4x+11
Answer:
The equation of the perpendicular line to y=-4*x-5 is [tex]y=\frac{1}{4}*x+\frac{7}{2}[/tex]
Step-by-step explanation:
Perpendicular lines are two or more lines that intersect at an angle of 90 degrees. Being y = m * x + b the equation of a line, two lines, with a slope other than zero, are orthogonal or perpenducillary if and only if the product of their slopes is -1. In other words, if two lines are perpendicular, they have their slopes reversed and sign changed.
In this case, with y = -4x-5 the slope will be -4. So the slope of the perpendicular line will be [tex]\frac{1}{4}[/tex]. Then the equation of the perpendicular line will be:
[tex]y=\frac{1}{4}* x+b[/tex]
To find the value of b, you know the value of the point (-2,3). So x = -2 and y = 3. Replacing in the equation of the perpendicular line, you have:
[tex]3=\frac{1}{4}* (-2)+b[/tex]
Solving, you get:
[tex]3=-\frac{1}{2}+b[/tex]
[tex]3+\frac{1}{2}=b[/tex]
[tex]\frac{7}{2}=b[/tex]
The equation of the perpendicular line to y=-4*x-5 is [tex]y=\frac{1}{4}*x+\frac{7}{2}[/tex]
WILL GIVE BRAINLIEST LOOK AT PHOTOS FOR QUESTION
Answer:
7.60
0.76
0.2
0.2
hjlai
Kevin is planting 15 bushes and 9 trees in rows if he wants all the rows the same with no plants left over what is the greatest number of rows kevin can plant
Which is the graph of y-3=-2/3(x+6)
Solve.
D = HS, for s
Answer:
The answer is S=D/H
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
3. A large banquet room holds 288 people, with each table seating 8. How many tables can the banquet hall have without going over its capacity? Maneuvering the Middle LLC.
Answer: 36 tables
Step-by-step explanation: Just divide 288 by 8. I hope this helps!
Help please!!!! I’ll give brainilest
Helpppppp!!!!!!!!!!!!
Answer:
b or B is correct answer out of all
Answer:
I'll try my best to answer this but it could be A. and B.
Step-by-step explanation:
The reasoning for this is because both A and B show correct number lines and the question is asking to select TWO that applyFor A., -2 is the opposite of 2»(-2 is on the left side of the number line, the left side of number lines show negative numbers)
This same rule applys to B. -4 is the opposite of 4.The reason why C. wouldn't be right is because -3 is on the same side where positive numbers would go, on the right side of 0. Meaning C. isn't a correct number line so it can't be the right answer..
I hope this helped!!
Determine the dimensions of a rectangular solid (with a square base) with maximum volume if its surface area is 181.5 square centimeters
Answer:
The base and height of the solid is 5.5cm
Step-by-step explanation:
Given
[tex]Surface\ Area = 181.5cm^2[/tex]
Required
Determine the dimensions that maximizes the volume
Let the base dimension be x and the height be h
The volume is calculated as:
[tex]Volume =x^2 * h[/tex]
[tex]Volume =x^2h[/tex]
181.5 =x^2h
The surface area (S) is calculated as this:
[tex]S = 2(x^2 + xh + xh)[/tex]
[tex]S = 2(x^2 + 2xh)[/tex]
[tex]S = 2x^2 + 4xh[/tex]
Substitute 181.5 for S
[tex]181.5 = 2x^2 + 4xh[/tex]
Make h the subject:
[tex]4xh = 181.5 - 2x^2[/tex]
[tex]h = \frac{181.5 - 2x^2}{4x}[/tex]
Substitute [tex]h = \frac{181.5 - 2x^2}{4x}[/tex] in [tex]Volume =x^2h[/tex]
[tex]V = x^2(\frac{181.5 - 2x^2}{4x})[/tex]
[tex]V = x(\frac{181.5 - 2x^2}{4})[/tex]
[tex]V = \frac{1}{4}(x)(181.5 - 2x^2)[/tex]
[tex]V = \frac{181.5x}{4} - \frac{2x^3}{4}[/tex]
[tex]V = \frac{181.5x}{4} - \frac{x^3}{2}[/tex]
To get the maximum, we differentiate V with respect to t and set the differentiation to 0
[tex]dV = \frac{181.5}{4} - \frac{3x^2}{2}[/tex]
Set to 0
[tex]0 = \frac{181.5}{4} - \frac{3x^2}{2}[/tex]
[tex]\frac{3x^2}{2} = \frac{181.5}{4}[/tex]
Multiply through by 4
[tex]4 * \frac{3x^2}{2} = \frac{181.5}{4} * 4[/tex]
[tex]2*3x^2 = 181.5[/tex]
[tex]6x^2 = 181.5[/tex]
[tex]x^2 = \frac{181.5}{6}[/tex]
[tex]x^2 = 30.25[/tex]
[tex]x = \sqrt{30.25[/tex]
[tex]x = 5.5[/tex]
Recall that:
[tex]h = \frac{181.5 - 2x^2}{4x}[/tex]
[tex]h = \frac{181.5 - 2 * 5.5^2}{4 * 5.5}[/tex]
[tex]h = \frac{181.5 - 60.5}{22}[/tex]
[tex]h = \frac{121}{22}[/tex]
[tex]h = 5.5[/tex]
So, we have:
[tex]h = 5.5[/tex]
[tex]x = 5.5[/tex]
Hence, the base and height of the solid is 5.5cm
The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.
When d=6, T=5
Find the value of T when d=3
Input note: give your answer correct to 2 decimal place.
Answer: T= 3.54
Step-by-step explanation:
Step 1
Given that
The time period, T, s doirectly proportional to the square root of the length, d, of the pendulum, we have that
T ∝ [tex]\sqrt{d}[/tex]
Introducing the constant of proportionality, we have that
T= K[tex]\sqrt{d}[/tex].
Step 2
When d=6, T=5, K =?
T= K[tex]\sqrt{d}[/tex].
5 = k[tex]\sqrt{6}[/tex]
5= k x 2.44949
k =5/2.44949
k =2.041
Therefore, when d = 3 , T= ?
T= K[tex]\sqrt{d}[/tex]
T= 2.041 x [tex]\sqrt{3}[/tex]
T= 3.53511≈ 3.54
(2^2)^4+3^3*3^3-43+85^2/85^2+23+445+54=?
Answer:
(2^2)^4+3^3*3^3-43+85^2/85^2+23+445+54= the answer is 1465
Drag and drop each number to its correct position on the number line.
i forgot the number line, so sorry
Answer:
-⅜ is between -1 and 0
⅞ is between 0 and 1
-2½ is between -3 and -2 ( in the mid )
2½ is between 2 and 3 ( in the mid )
help please help asap
Answer:
14/20 = 7/10 so I believe it would be 7 days out of 10
Step-by-step explanation:
Answer:
Wouldn't it be 14/20
Step-by-step explanation:
а
ا ن و و
An account paying 4.6% interest compounded quarterly has a balance of $506,732.32. Determine the amount that
can be withdrawn quarterly from the account for 20 years, assuming ordinary annuity.
$9,722.36
b $6,334.15
$23,965.92
d. $7,366.99
Answer:
answer Option A $9,722.36
I am 100% sure
Picture Shown!! Please help!!
Answer:
64x^6
Step-by-step explanation:
Which expressions are equivalent to
?
2
Choose 2 answers:
MY
Coi
k-2
MY
Pro
Pra
Tea
k: 2
k+k
Which statement does not describe the cosine function?
A. The cycle repeats every 21 radians.
B. Its range includes all real numbers.
C. The cycle starts at y = 1, decreases to y = -1, and then increases
to y = 1.
D. Its reciprocal function is secant.
SUBMIT
The statement (B) " Its range includes all real numbers." is correct because it does not describe the cosine function.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
As we know, the trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.
Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
The domain of a cos function is al real numbers and the range of the cos function is [-1, 1]
The cos function is the reciprocal of the secant.
The cycle repeats every 21 radians.
Thus, the statement (B) " Its range includes all real numbers." is correct because it does not describe the cosine function.
Learn more about the function here:
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Help with this puzzle for Brainliest!
Question on the attachment.. Please help
Answer:
yehh it would be efffective
Stephanie spends $15 each month to belong to a photography club. As a member of the club she can develop rolls of film for $2.50 each. Write and solve an equation to find the total amount Stephanie will spend this month if she develops 5 rolls of film.
Answer:
2.5*5= 12.5
15-12.5=2.5
So in order to pay the 15 dollars in the photography club, she only has to pay 2.50
Write and solve an equation to find the number of miles you must drive to have the same cost for each of the car rentals. Let m represent the number of miles. $20+.50 per mile and $30+.25 permile
Answer:
equation: 20+0.50x=30+0.25x
answer: 40 miles
Step-by-step explanation:
i'm a math genius
Piper opened a savings account with $1400 that pays no interest. She deposits an
additional $50 each week thereafter. How much money would Piper have in the
account 47 weeks after opening the account?
Answer:
$3700
Step-by-step explanation:
Given that:
Initial amount = $1400
Amount deposited per week = 50
Amount after 47 weeks =?
Using the Arithmetic Progression relation :
Tn = A + (n - 1)d
Weekly deposit = d = 50
A = initial / first deposit = 1400
n = number of deposits
T47 = 1400 + (47 - 1)50
T47 = 1400 + (46)*50
T47 = 1400 + 2300
T47 = 3700
Answer:
$3750
Step-by-step explanation:
T47 = 3750
Please help, worth 20+! GIVE ANWERS! PLEASE ANDty
[tex]\huge\underbrace\mathtt\blue{∆ᴀɴsᴡᴇʀ∆}[/tex]
[tex]1) \: \: \: \frac{34}{100} = 0.34[/tex]
[tex]2) \: \: \: \: \frac{23}{50} = \frac{23 \times 2}{50 \times 2} = \frac{46}{100} = 0.46[/tex]
[tex]3) \: \: \: \frac{6}{8} = \frac{6 \times 125}{8 \times 125} = \frac{750}{1000} = 0.008[/tex]
[tex]4) \: \: \: \frac{1}{3} = 0.3[/tex]
(for no. 4 check the image in the attachment)
I GIVEEEEEEEEEEEEEEEEEE BRAAINLILSTER
Answer:
thx for giving brainliest
A side of the triangle below has been extended to form an exterior angle of 127°. Find
the value of x.
17°
xº
127°
Answer:
x = 53°
Step-by-step explanation:
x + 127° = 180° (sum of angles on a straight line/supplementary angles)
Subtract 127 on both sides
x + 127 - 127 = 180 - 127 (subtraction property of equality)
x = 53°
3x+2/2=13 please help me find the anwser
Answer:
x=4
Step-by-step explanation:
inverse laplace of L^-1 {5s/s^2 + 3s - 4}
Answer:
[tex]e^{t}+4e^{-4t}[/tex].
Step-by-step explanation:
To find the Laplace inverse of the above problem, we have to first solve the problem as a partial fraction, hence:
[tex]\frac{5s}{s^2+3s-4}=\frac{5s}{s^2+4s-s-4} \\\\=\frac{5s}{s(s+4)-1(s+4)}\\\\=\frac{5s}{(s-1)(s+4)}=\frac{A}{s-1}+\frac{B}{s+4}\\\\= \frac{A(s+4)+B(s-1)}{(s-1)(s+4)}\\\\Hence:\\\\\frac{A(s+4)+B(s-1)}{(s-1)(s+4)}=\frac{5s}{(s-1)(s+4)}\\\\A(s+4)+B(s-1)=5s\\\\to\ find \ A,put\ s=1:\\\\A(1+4)+B(1-1)=5(1)\\\\5A=5\\\\A=1\\\\to\ find \ B,put\ s=-4:\\\\A(-4+4)+B(-4-1)=5(-4)\\\\-5B=-20\\\\B=4\\\\Hence:\\\\\frac{5s}{s^2+3s-4}=\frac{1}{s-1}+ \frac{4}{s+4}\\\\[/tex]
[tex]L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]\\\\But\ L^{-1}[\frac{1}{s-a} ]=e^{at}\\\\Hence:\\\\L^{-1} [\frac{5s}{s^2+3s-4}]=L^{-1}[\frac{1}{s-1} ]+L^{-1}[\frac{4}{s+4} ]=e^{t}+4e^{-4t}\\\\=e^{t}+4e^{-4t}[/tex]