Answer:
A) б1 = 28 ksi and б2 = -6.02 ksi
B) 1.25
Explanation:
Given data :
Torsional stress = 13 ksi
Alternating bending stress = 22ksi
A) determine yielding factor of safety according to the distortion energy theory
б1,2 = [tex]\frac{22}{2}[/tex] ± √(22/2)² + 13²
= 11 ± 17
therefore б1 = 28 ksi hence б2 = -6.02 ksi
B) determine the fatigue factor of safety
with properties ; Se = 35ksi, Sy = 60 ksi, Sut = 85 ksi
( б1 - б2 )² + ( б2 - б3 )² + ( б3 - б1 )² ≤ 2 ( Sy / FOS ) ²
( 28 + 6.02 ) ² + ( 6.02 - 0 )² + ( 0 - 28 )² ≤ 2 ( 60 / FOS ) ²
solving for FOS = 1.9
Next we can determine FOS with the use of Goodman criterion
бm / Sut + бa / Se = 1 / FOS
= 0 / 85 + 28/35 = 1 / FOS
making FOS the subject of the equation ; hence FOS = 1.25
A genetically engineered hormone.
increasing muscle mass.
can treat Mary's child for growth hormone deficiencies by stimulating body growth and increasing muscle mass.
Answer:
the answer is scientifically science chemistry biochemistry aerospace engineering plato english history world ap history yes
Explanation:
que
Merchants get commission from selling products that are consigned to them true or false
Answer:
true
Explanation:
Tech A says that you can test for defective ignition wires by using a spray bottle and water. Tech B says that you can test for defective ignition wires with a grounded test lead. Who is correct?
A) Tech A
B) Tech B
C) Both Techs A and B
D) Neither Tech A nor B
Answer: C) Both Techs A and B
Explanation:
Technician A and Technician B are both very right. Using a spray bottle and water, the ignition wire test can be carried out using any of the methods described above. Or, by using a grounded test lead that is connected to a multimeter, you can also conduct the test for faulty ignition wires.
Answer: Either A or B
Explanation:
Why did Percy most likely send Medusa's head to Olympus when he knew this would upset the gods?
Answer: To show his father what he had done
Explanation:
Percy Jackson is the son of the great Greek god of the seas, Poseidon. He did not however, know this for a long time. After he finds out, his life becomes more exciting as he embarks on many adventures.
According to Grover who is his best friend and guardian, Percy sent Medusa's head to Mount Olympus to show his father what he had done so that Poseidon would acknowledge and be proud of him.
Find the resultant of two forces 130 N and 110 N respectively, acting at an angle whose tangent
is 12/5.
Answer:
[tex]F_r = 200N[/tex]
Explanation:
Given
Let the two forces be
[tex]F_1 = 130N[/tex]
[tex]F_2 = 110N[/tex]
and
[tex]\tan(\theta) = \frac{12}{5}[/tex]
Required
Determine the resultant force
Resultant force (Fr) is calculated using:
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]
This means that we need to first calculate [tex]\cos(\theta)[/tex]
Given that:
[tex]\tan(\theta) = \frac{12}{5}[/tex]
In trigonometry:
[tex]\tan(\theta) = \frac{Opposite}{Adjacent}[/tex]
By comparing the above formula to [tex]\tan(\theta) = \frac{12}{5}[/tex]
[tex]Opposite = 12[/tex]
[tex]Adjacent = 5[/tex]
The hypotenuse is calculated as thus:
[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex]
[tex]Hypotenuse^2 = 12^2 + 5^2[/tex]
[tex]Hypotenuse^2 = 144 + 25[/tex]
[tex]Hypotenuse^2 = 169[/tex]
[tex]Hypotenuse = \sqrt{169[/tex]
[tex]Hypotenuse = 13[/tex]
[tex]\cos(\theta)[/tex] is then calculated using:
[tex]\cos(\theta)= \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos(\theta)= \frac{5}{13}[/tex]
Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]cos(\theta)[/tex] in
[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]
[tex]F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}[/tex]
[tex]F_r^2 = 16900 + 12100 + 11000[/tex]
[tex]F_r^2 = 40000[/tex]
Take square roots of both sides
[tex]F_r = \sqrt{40000[/tex]
[tex]F_r = 200N[/tex]
Hence, the resultant force is 200N
Anthony and Angel are making plans for Friday. Anthony wants to go bowling. Angel doesn't bowl well and prefers to go ice-skating at the mall.
Anthony wants Angel to have a good time so he agrees ice-skating will be fun for both of them. Anthony's decision to go ice-skating is an example
of
O evaluation
O arbitration
Omed ation
O compromise
Answer:
4. Compromise
Explanation:
A compromise is when the two disagreeing parties give up something to make a conclusion that both are satisfied with. In this case, Anthony wants Angel to have a good time, so he gives up his bowling.
Cast iron has about how much carbon content?
A)Less than 1%
B)2%
C)3%
D)4% or higher
Answer:
c
Explanation:
Which size lug nut would fit a metric wheel stud?
A)7/16-20 LH
B)½ X20
C)M12X 1.5
D)7/16-20RH
In I-Q modulation technique, many symbols or signals with different amplitude and phase are generated. What is the map of all of the symbols called:____.
a. signal diagram.
b. frequency spectrum.
c. 2-D graph.
d.constellation diagram.
Answer:
In I-Q modulation technique, many symbols or signals with different amplitude and phase are generated. What is the map of all of the symbols called:____.
d. constellation diagram.
Explanation:
A constellation diagram is a representation of all the possible symbols that a system can transmit. It shows these as a collection of points on the map. For a signal modulated by a digital modulation scheme, the constellation diagram is used to display both the ideal (reference) signal and the actual measured signal on the same plot. Modulation simply means the process of converting data into electrical signals so that they are optimized for transmission.
Schrodinger equation is a ........... Equation
Answer:
linear partial differential
Explanation:
The Schrödinger equation is a linear partial differential equation that describes the wave function or state function of a quantum-mechanical system. It is a key result in quantum mechanics, and its discovery was a significant landmark in the development of the subject.
Two blocks, one 0.8 kg and the other 2.0 kg are connected by a massless string over a frictionless pulley. The coefficient of kinetic friction is 0.14, and the downward ramp angle is 60 degrees.
a. Determine the acceleration of the blocks.
b. Calculate the tension of the string.
Answer:
a) 4.58m/s²
b) 10.454N
Explanation:
According to Newton second law, the following simultaneous equation will be applicable
T - Fm = m1a.... 1
W - T = m2a ....2
m1 and m2 are the masses
T is the tension of the string
W is the weight of mass m2
Fm is the force acting along the incline
Fm = m1gsin theta
W = m2g
a) Add both equation to eliminate tension T
W-Fm = m1a+m2a
m2g - m1gsin theta = (m1+m2)a
Substitute the given values
2(9.8)-0.8(9.8)sin60 = (2+0.8)a
19.6-6.79 = 2.8a
12.81 = 2.8a
a = 12.81/2.8
a = 4.58m/s²
Hence the acceleration of the blocks is 4.58m/s2
b) Get the Tension T
Substitute the acceleration gotten in (a) into equation 1 as shown:
From 1:
T - Fm = m1a
T = m1a+Fm
T = 0.8(4.58)+m1gsintheta
T = 0.8(4.58)+0.8(9.8)sin60
T = 3.664+6.79
T = 10.454N
Hence the tension in the string is 10.454N
Considering only (110), (1 1 0), (101), and (10 1 ) as the possible slip planes, calculate the stress at which a BCC single crystal will yield if the critical resolved shear stress is 50 MPa and the load is applied in the [100] direction.
Solution :
i. Slip plane (1 1 0)
Slip direction -- [1 1 1]
Applied stress direction = ( 1 0 0 ]
τ = 50 MPa ( Here slip direction must be perpendicular to slip plane)
τ = σ cos Φ cos λ
[tex]$\cos \phi = \frac{(1,0,0) \cdot (1,1,0)}{1 \times \sqrt2}$[/tex]
[tex]$=\frac{1}{\sqrt2 }$[/tex]
[tex]$\cos \lambda = \frac{(1,0,0) \cdot (1,-1,1)}{1 \times \sqrt3}$[/tex]
[tex]$=\frac{1}{\sqrt3 }$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
ii. Slip plane --- (1 1 0)
Slip direction -- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, -1, 0)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
iii. Slip plane --- (1 0 1)
Slip direction --- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, 1)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
iv. Slip plane -- (1 0 1)
Slip direction ---- [1 1 1]
[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, -1)}{1 \times \sqrt2}=\frac{1}{\sqrt2}$[/tex]
[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, -1, 1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]
τ = σ cos Φ cos λ
∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]
σ = 122.47 MPa
∴ (1, 0, -1). (1, -1, 1) = 1 + 0 - 1 = 0
is used to change physical objects and 3-D ideas into 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.
Answer:
2D CAD Software Application
Explanation:
Two Dimensional Computer-Aided Design Software Application is otherwise known as 2D CAD software application such as AutoCAD or MicroStation is used to change physical objects and 3-D ideas into a 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.
The utilization of a 2D CAD software application saves time and revision to construction drawings can quickly be made without having to redesign the whole drawings from the scratch.
ldentiy three industries that often need the skills of mechanical engineers. Briefly explain the skills that mechanical engineers bring to these
industries.
Answer:
3 industries that often need the skills of mechanical engineers are:
Automotive industry Construction industry Aerospace industryThe key skills mechanical engineers bring to these industries are effective technical skills, the ability to work under pressure, problem-solving skills, creativity and teamwork.
Explanation:
Automotive industry: The skills mechanical engineers bring to automotive industry include designing new cars for development, conducting laboratory testing for performance safety, and troubleshooting design or manufacturing issues with recalled vehicles. Automotive engineers have:
good mathematical skills, for instance in calculating the stresses power trains and other parts have to withstand; understanding and application of principles of physics and chemistry to properly design engines, electrical systems and other car components; good computer skills, because 21st century engineers rely on computer-assisted design software; knowledge of ergonomics, which is applied in the process of designing a car so that the driver and passengers have a comfortable and functional environment, is another skill mechanical; engineers need.Construction industry: Mechanical engineers are responsible for designing, building, establishing, and maintaining all kinds of mechanical machinery, tools, and components in the construction industry.
Aerospace industry: Mechanical engineers in aerospace industry produce specifications for design, development, manufacture and installing of new or modified mechanical components or systems. They design more fuel-efficient aircraft that cut emissions and build the fleets of satellites that power modern GPS technology.
Estimate the heating energy requirements for a residential building using the degree-day method (a) in Denver, Colorado, and (b) in Little Rock, Arkansas. The overall heat loss coefficient is 400 Btu/h.oF and the furnace efficiency is 0.78.
Answer:
a) 600°F days
b) 103°F days
Explanation:
Given data :
overall heat loss coefficient = 400 Btu/h.oF
Furnace efficiency = 0.78
applying the degree- day method the heating energy requirement per day can be obtained by subtracting the average temperature for a particular day from the acceptable mid/balance point temperature
lets assume the mid/balance point temperature = 65°F
a) heating energy requirement in Denver Colorado
we will have 600°F days ; considering the the average temperature - balance point temperature
= 665 - 65 = 600°F
b) heating energy requirement in Little Rock Arkansas
we will have 103° days
A section of highway has a speed-flow relationship of the form q = au 2 + bu. It is known that at capacity (which is 3100 veh/h) the space-mean speed of traffic is 28 mi/h. Determine the speed when the flow is 1500 veh/h and the free-flow speed.
Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. Which international organizations would it MOST LIKELY turn to? A. UNDP or UNICEF B. World Bank or UNICEF C. UNDP or World Bank D. UNDP or IMF
Answer:
C. UNDP or World Bank.
Explanation:
Suppose the country of Bangladesh wants a low interest loan to invest in the building of infrastructure. The international organizations which Bangladesh would most likely turn to are UNDP or World Bank.
The peak voltage of a 240 vrms sine wave is approximately
Answer:
339.4625
Explanation:
correct me if i am wrong
A light aircraft with a wing area of 200 ft^2 and a weight of 2000 lb has a lift coefficient of 0.39 and a drag coefficient of 0.06. Determine the power required to maintain level flight.
Answer: power required to maintain level flight=82.20hp
Explanation:
Given
Area = 200 ft^2
Weight = 2000 lb
Cl( Lift coefficient)= 0.39
Cd( Drag coefficient) = 0.06
The density ρ of air at standard atmospheric pressure = 2.38 X 10^-3 slugs/ft^3
For Equilibrium to be maintained during flight conditions, the lift force must be balanced by the weight of the aircraft such that
Lift force = Weight of aircraft
(1/2)ρAU²Cl= W
1/2X 2.38 X 10^-3 X 200 X U² X 0.39 = 2000
U²= 2000 X 2 / 2.38 X 10^-3 X 200 X 0.39
U=[tex]\sqrt{21,547.08}[/tex]
Velocity, U= 146.7892ft/s
Drag force of the velocity can be deduced from the formulae
Cd= Drag force(D) /1/2 ρU²A
Drag force=1/2 ρU²ACd
D=1/2 x (2.38 X 10^-3 slugs/ft^3) x (146.7892ft/s)² x 200 ft^2 x 0.06
D=307.69
Drag force= 308lb
power required to maintain level flight is given as
P = Drag force x Velocity = D x U
=308lb X 146.7892ft/s
=45,211.0736lb.ft/s
Changing to hp we have that
1 Horsepower, hp = 550 ft lbf/s
??=45,211.0736lb.ft/s
45,211.0736lb.ft/s/ 550 ft lbf/s= 82.20hp
Which of the following would be seen as an improvement on the quality of capital or a positive investment? A. Educational test scores are up. B. An assembly line has been closed down. C. Research and development has improved. D. Irrigation systems have been installed.
Answer:
The correct option is;
D. Irrigation systems have been installed
Explanation:
The quality of capital measures the amount of capital available within an economy and the benefit derivable from the capital
Quality of capital is improved by advances in technology which are the outcomes of research and development. With technological advancement, a unit of capital can enable a unit of labor to increase the amount of goods produced
The difference between a farm which uses manual labor to water the plants and a farm which uses an irrigation system is that the farm that uses manual watering techniques has a lower quality of capital per worker than the farm that has an irrigation system, which is a positive investment.
Solve for R.
What is the current going through the 6 ohms light bulb?
Answer:
9A
Explanation:
A reversible steady-state device receives a flow of 1 kg/s air at 400 K, 450 kPa and the air leaves at 600 K, 100 kPa. Heat transfer of 900 kW is added from a 1000 K reservoir, 50 kW is rejected at 350 K, and some heat transfer takes place at 500 K. Find the heat transferred at 500 K and the rate of work produced.
Answer:
41 kW
690.2 kW
Explanation:
Given the following data
T1 = 400 K
P1 = 350 kPa
T2 = 600 K
P2 = 100 kPq
m = 1 kg/s
Q1 = 900 kW
Q2 = 50 kW
T(amb1) = 1000 K
T(amb2) = 350 K
T(amb3) = 500 K
We also will be using tables to solve the question.
R = 0.287 kJ/kgk
C(p) = 1.004 kJ/kgk
To find Q3, we'd use the formula
Q3 = m.T(amb3).[C(p).In(T2/T1) - R.In(P2/P1)] - [T(amb3)/T(amb1) * Q1] + [T(amb3)/T(amb2) * Q2]
Q3 = 1 * 500 * [1.004 * In(600/400) - 0.287 * In(100/450)] - 500/1000 * 900 + 500/350 * 50
After simplification, we find that
Q3 = 41 kW
Next, we use the equation
Q3 - Q2 + Q1 = W + m.C(p).(T2 - T1)
41 - 50 + 900 = W + 1 * 1.004 * (600 - 400)
891 = W + 1.004 * 200
891 = W + 200.8
W = 891 - 200.8
W = 690.2 kW
If we make W the subject of the formula, we have
How would you handle a situation where another team member was critical of your work?
What is the preferred approach to risk mitigation?
-Tolerate
-Transfer
-Terminate
-Treat
Answer:
The correct option is;
Terminate
Explanation:
Termination of the risk is equivalent to elimination of the risk by avoiding the activity that brings about the risk or by using a different process that does not include the risk observed in the previous process option
When the reward far outweigh the risk, it may be decided to terminate or eliminate the risk and miss the reward and also terminate the likelihood of the losses to be incurred.
For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion
This question is incomplete, the complete question is;
For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion
y = 1 - exp( -ktⁿ )
Answer: the time required for 95% transformation is 242.17 s
Explanation:
First, we calculate the value of k which is the dependent variable in Avrami equation
y = 1 - exp( -ktⁿ )
exp( -ktⁿ ) = 1 - y
-ktⁿ = In( 1 - y )
k = - In( 1 - y ) / tⁿ
now given that; n = 2, y = 40% = 0.40, and t = 100 s
we substitute
k = - In( 1 - 0.40 ) / 100²
k = - In(0.60) / 10000
k = 0.5108 / 10000
k = 0.00005108 ≈ 5.108 × 10⁻⁵
Now calculate the time required for 95% transformation
tⁿ = - In( 1 - y ) / k
t = [- In( 1 - y ) / k ]^1/n
n = 2, y = 95% = 0.95 and k = 5.108 × 10⁻⁵
we substitute our values
t = [- In( 1 - 0.95 ) / 5.108 × 10⁻⁵ ]^1/2
t = [2.9957 / 5.108 × 10⁻⁵]^1/2
t = [ 58647.22 ]^1/2
t = 242.17 s
Therefore the time required for 95% transformation is 242.17 s
What can be used as a tracing powder when checking for small oil leaks
Answer:
Talcum powder!
Explanation:
How to find the source of an oil leak:
This method simply involves using Talcum Powder as a visual aid to help pinpoint the location of an oil leak,
so you use Talcum powder for small oil leak :]
Have a wonderful day!
Which of the following is the property that describes the amount of volume that decreases when pressure is applied to a fluid?
O shear stress
O compressibility
O viscosity
O elasticity
Answer:
Compressibility.
Explanation:
The compressibility of a fluid can be defined as a measure of the change in volume (density) with respect to the amount of pressure applied to the fluid. Thus, as the pressure of a compressible fluid increases, both its viscosity and density increases.
Some examples of compressible fluids are vapors, gases, air etc.
Hence, compressibility is the property that describes the amount of volume that decreases when pressure is applied to a fluid.
Additionally, the compressibility of fluids plays a significant role in the field of science such as in aerodynamics, fluid mechanics, thermodynamics etc.
Answer:
compressiblity
Explanation:
The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elasticity of the metal and oxide are, respectively, 57 GPa and 390 GPa, what is the (a) upper-bound, and (b) lower-bound modulus of elasticity values (in GPa) for a composite that has a composition of 33 vol% of oxide particles.
Answer:
a) the modulus of elasticity upper-bound is 166.89 GPa
b) the modulus of elasticity lower-bound is 79.36 Gpa
Explanation:
For a two-phase composite, modulus of elasticity upper-bound expression is as follows;
Ec(U) = EmVm + EpVp
where Em is the modulus of elasticity of matrix, Ep is the modulus of elasticity of patriciate phase, Ec is the modulus of elasticity of composite, Vm is the volume fraction of matrix and Vp is the volume fraction of composite.
Also for a two-phase composite, modulus of elasticity lower-bound expression is as follows;
Ec(L) = (EmEp) / ( VmEp + VpEm)
a)
Now lets consider the expression of rule of mixtures for upper-bound and calculate the modulus of elasticity upper-bound.
Ec(U) = EmVm + EpVp --------- equ 1
Vm + Vp = 1
given that Vp = 33 vol% = 0.33, we substitute
Vm + 0.33 = 1
Vm = 0.67
so from our equation 1
we substitute our given data; Em = 57 Gpa, Ep = 390 Gpa, Vm = 0.67, Vp = 0.33
Ec(U) = EmVm + EpVp
Ec(U) = ( 57 × 0.67) + ( 390 × 0.33)
Ec(U) = 38.19 + 128.7
Ec(U) = 166.89 GPa
Therefore the modulus of elasticity upper-bound is 166.89 GPa
b)
Now lets consider the expression of rule of mixtures for lower-bound and calculate the modulus of elasticity upper-bound.
Ec(L) = (EmEp) / ( VmEp + VpEm)
we substitute our values
Ec(L) = (57 × 390) / ( (0.67 × 390) + (0.33 × 57)
Ec(L) = 22230 / ( 261.3 + 18.81)
Ec(L) = 22230 / 280.11
Ec(L) = 79.36 Gpa
Therefore the modulus of elasticity lower-bound is 79.36 Gpa
A W18 X 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the design compressive strength of A992 steel is used
Answer:
156.0 ksi
Explanation:
The formula of compressive strength is CS = F / A
where F is the force or load while A is the cross-sectional area
Given the inertia Ag = 35.1 in^4 , which is less than 40, the steel has a short column.
E = 29000 ksi
L = 12ft
r = 2.69 in
therefore;
CS = π^2 E / (kL^2/r)^2
= π^2 29000 / (0.8 x 12^2 / 2.69)^2
= 286292.756 / 1834.4089 = 156 ksi
A motorist is driving his car at 60km/hr when he observes that a traffic light 250m ahead turns red. The traffic light is
timed to remain red for 20 seconds before it turns green. The motorist wishes to pass the traffic lights without stopping to wait for it to turn green. make calculations for
(a) the required uniform acceleration of the car
(b) the speed of the car as it passes the traffic light in km/hr
Explanation:
Okay soo-
Given-
u = 60 km/hr = 60×1000/3600=50/3 m/s
t = 20 s
s = 250 m
a = ?
v = ?
Solution -
Here, acceleration is uniform.
(a) According to 2nd kinematics equation,
s = ut + ½at^2
250 = 50/3 ×20 + 0.5×a×20×20
250-1000/3=200a
(750-1000)/3=200a
a = -250/(3×200)
a = -5/12
a = 0.4167 m/s^2
The required uniform acceleration of the car is 0.4167 m/s^2.
(b) According to 1st kinematics equation
v = u + at
v = 50/3 + (-5/12)×20
v = 50/3-25/3
v = 25/3
v = 8.33 m/s
The speed of the car as it passes the traffic light is 8.33 m/s.
Good luck!