A car travels 87 miles north and
then 114 miles west.
What is the direction of the car's
resultant vector?
Hint: Draw a vector diagram.
0 = [?]
Round your answer to the nearest hundredth.
Enter

Answer:

5

Step-by-step explanation:

let x = missing exponent

x - 2 + 1 = 4

x -1 = 4

x = 5

The general solution of the given second-order differential equation is:

y = c₁e^x + c₂e^(2x)

The given second-order differential equation is:

y'' − 3y' + 2y = 0

To solve this differential equation, we will first find its characteristic equation by assuming a solution of the form y = e^(rx), where r is a constant. Substituting this into the differential equation, we get:

r²e^(rx) − 3re^(rx) + 2e^(rx) = 0

Factoring out e^(rx), we have:

e^(rx) (r² − 3r + 2) = 0

For this equation to hold true for all values of x, the term in the parentheses must be equal to zero:

r² − 3r + 2 = 0

We can factorize this quadratic equation:

(r - 1)(r - 2) = 0

Setting each factor to zero, we find the roots of the characteristic equation:

r = 1 and r = 2

Therefore, the general solution of the given second-order differential equation is:

y = c₁e^x + c₂e^(2x)

where c₁ and c₂ are arbitrary constants that can be determined using the initial conditions of the differential equation.

To verify this solution, you can substitute y = e^(rx) into the given differential equation and solve for r. You will find that the characteristic equation is satisfied by the roots r = 1 and r = 2, confirming the validity of the general solution.

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The determinant of the given matrix is 15.

By observing the matrix [4 6 -1 2 3 2 1 -1 1], we get the value of the determinant to be 15.

To verify this result, we can compute the determinant as follows:`Δ = [4(3(-1) - (-1)(2)) - 6(2(-1) - 1(2)) + (-1)(2(2) - 3(1))]

`Expanding the equation, we get: `Δ = [4(-5) - 6(-6) + (-1)(-1)]`

Δ = [-20 + 36 - 1]

`Δ = 15`

Therefore, the determinant of the given matrix is 15.

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The unique solution to the initial value problem is: y = 1 + x + 6x².

To solve the non-homogeneous problem y" = 12(2x²), let's go through the steps:

1) Homogeneous problem:

The homogeneous equation is y" = 0. The auxiliary equation is ar² + br + c = 0.

2) The roots of the auxiliary equation:

Since the coefficient of the y" term is 0, the auxiliary equation simplifies to just c = 0. Therefore, the root of the auxiliary equation is r = 0.

3) Fundamental set of solutions:

For the homogeneous problem y" = 0, since we have a repeated root r = 0, the fundamental set of solutions is Y₁ = 1 and Y₂ = x. So the complementary solution is Yc = C₁(1) + C₂(x) = C₁ + C₂x, where C₁ and C₂ are arbitrary constants.

4) Particular solution:

To find a particular solution, we can use the method of undetermined coefficients. Since the non-homogeneous term is 12(2x²), we assume a particular solution of the form yp = Ax² + Bx + C, where A, B, and C are constants to be determined.

Taking the derivatives of yp, we have:

yp' = 2Ax + B,

yp" = 2A.

Substituting these into the non-homogeneous equation, we get:

2A = 12(2x²),

A = 12x² / 2,

A = 6x².

Therefore, the particular solution is yp = 6x².

5) General solution and initial value problem:

The general solution is the sum of the complementary solution and the particular solution:

y = Yc + yp = C₁ + C₂x + 6x².

To solve the initial value problem y(0) = 1 and y'(0) = 1, we substitute the initial conditions into the general solution:

y(0) = C₁ + C₂(0) + 6(0)² = C₁ = 1,

y'(0) = C₂ + 12(0) = C₂ = 1.

Therefore, the unique solution to the initial value problem is:

y = 1 + x + 6x².

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The length of CE in triangle ADE is 16.00 units when rounded to the nearest hundredth.

To find the length of CE in triangle ADE, we can make use of similar triangles and proportional relationships. Since BC is parallel to DE, we have triangle ABC and triangle ADE as similar triangles.

By the property of similar triangles, corresponding sides are proportional. Therefore, we can set up the following proportion:

AB/AD = BC/DE

Substituting the given values, we have:

8/AD = 8/CE

Cross-multiplying, we get:

8 * CE = 8 * AD

Dividing both sides by 8, we have:

CE = AD

To find AD, we can use the fact that AB + BD = AD. Substituting the given values, we get:

8 + 8 = AD

AD = 16

Therefore, CE = 16.

Rounding the answer to the nearest hundredth, CE = 16.00.

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You can upload a picture of the constructed angle of measure 320 degrees and the tool used to create it.

To construct an angle of measure 320 degrees on paper, follow these steps:

Step 1: Draw a straight line of arbitrary length using a ruler.

Step 2: Place the point of the protractor on one endpoint of the line. Align the base of the protractor with the line, ensuring that the zero mark of the protractor is at the endpoint of the line and the line of the protractor passes through the endpoint and the other end of the line.

Step 3: Locate and mark a point along the protractor's arc that corresponds to the measure of 320 degrees.

Step 4: Use the ruler to draw a line from the endpoint of the original line, passing through the marked point on the protractor's arc. This line will form an angle of 320 degrees with the original line.

Finally, you can upload a picture of the constructed angle of measure 320 degrees and the tool used to create it.

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a) The domain of the function f(x, y) = 6x²yT¹-4y² is determined by the condition T¹-4y² ≥ 0. The domain can be expressed as -√(T¹/4) ≤ y ≤ √(T¹/4). A sketch of the function requires more information about T¹ and any constraints on x.

b) To find the limit of the function as (x, y) approaches (0, 0), we substitute the values into the function and find that f(0, 0) = 0. However, to determine the existence of the limit, further analysis along different paths approaching (0, 0) is required. Without additional information, we cannot conclusively determine the limit.

a) To find the domain of the function f(x, y) = 6x²yT¹-4y², we need to determine the values of x and y for which the function is defined.

From the given function, we can see that the only restriction is on the term T¹-4y², which implies that the function is undefined when the expression T¹-4y² is negative, as we can't take the square root of a negative number.

Setting T¹-4y² ≥ 0, we solve for y:

T¹-4y² ≥ 0

4y² ≤ T¹

y² ≤ T¹/4

Taking the square root of both sides, we get:

|y| ≤ √(T¹/4)

So the domain of the function f(x, y) is given by:

Domain: -√(T¹/4) ≤ y ≤ √(T¹/4)

To provide a sketch, we would need additional information about the value of T¹ and any other constraints on x. Without that information, it's not possible to accurately sketch the function.

b) To find the limit of the function lim(x,y) → (0,0) f(x, y), we need to evaluate the function as the variables x and y approach zero.

Substituting x = 0 and y = 0 into the function f(x, y), we get:

f(0, 0) = 6(0)²(0)T¹-4(0)² = 0

The function evaluates to zero at (0, 0), which suggests that the limit might exist. However, to determine if the limit exists, we need to analyze the behavior of the function as we approach (0, 0) from different directions.

By examining various paths approaching (0, 0), if we find that the function f(x, y) approaches different values or diverges, then the limit does not exist.

Without further information or constraints on the function, we cannot definitively determine the limit. Additional analysis of the behavior of the function along different paths approaching (0, 0) would be required.

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The rule states that if a statement is true of an arbitrary object, then it is true of all objects.

An axiomatization by using and adding a rule of universal generalization is as follows:((∀1∀1) ∀x A→A(y/x) ∀x A→A(y/x), provided yy is free for xx in AA). Axiomatization in a theory is to provide a precise description of the objects, properties, and relationships that are meaningful in the field of study that the theory belongs to. In addition to the axioms, a formal theory may also specify certain rules of inference that allow us to derive new statements from old ones.

The addition of a rule of universal generalization to the system of axioms and rules of inference allows us to infer statements about all objects in a domain from statements about individual objects.  The generalization rule is as follows: If AA is any statement and xx is any variable, then ∀x A is also a statement. The variable xx is said to be bound by the universal quantifier ∀x. The quantifier ∀x binds the variable xx in statement A to the left of it.

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To solve the problem and calculate the original principal, we need more information or context. The options given (4406, 4718, 4500, none of them) seem to be potential values for the original principal, but there isn't any calculation or formula given to use.

In order to calculate the original principal, we typically need additional information such as the interest rate, the time period, and possibly the final amount or the interest earned. Without this information, we cannot determine the exact value of the original principal.

Hence for solving the given question we need sufficient amount of information in form of values to apply it in the given question and find the optimum and correct solution.

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The values of x and y in the given system of equations are x = 4.00 and y = 5.00. These values are obtained by solving the system using the method of substitution.

The given system of linear equations is:

0.50x + 0.20y = 3.00 ...(Equation 1)

x + y = 9.00 ...(Equation 2)

To solve this system of equations, we can use the method of substitution or elimination. Let's solve it using the method of substitution:

From Equation 2, we can express x in terms of y:

x = 9.00 - y

Substituting this expression for x in Equation 1, we have:

0.50(9.00 - y) + 0.20y = 3.00

Expanding and simplifying:

4.50 - 0.50y + 0.20y = 3.00

-0.30y = -1.50

Dividing both sides by -0.30:

y = -1.50 / -0.30

y = 5.00

Now, substitute this value of y back into Equation 2 to find x:

x + 5.00 = 9.00

x = 9.00 - 5.00

x = 4.00

Therefore, the values of x and y in the given system of equations are x = 4.00 and y = 5.00.

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Answer:

F(b) - F(a)

Step-by-step explanation:

[tex]F(x) = \int f(x) \, dx[/tex]

Answer:

Not specific enough... but it should be m = 15/(5a).

Step-by-step explanation:

To solve for m in the equation 5am = 15, we can isolate the variable m by dividing both sides of the equation by 5a:

5am = 15

Divide both sides by 5a:

(5am)/(5a) = 15/(5a)

Simplify:

m = 15/(5a)

Therefore, the solution for m is m = 15/(5a).

The shortest lengths of cables AB and AC that can be used for the lift are both 5.4 kN.

To determine the shortest lengths of cables AB and AC, we need to consider the maximum tension allowed in each cable, which is 5.4 kN.

The length of a cable is not relevant in this context since we are specifically looking for the minimum tension requirement. As long as the tension in both cables does not exceed 5.4 kN, they can be considered suitable for the lift.

Therefore, the shortest lengths of cables AB and AC that can be used for the lift are both 5.4 kN. The actual physical length of the cables does not impact the answer, as long as they are capable of withstanding the maximum tension specified.

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Step-by-step explanation:

-5x+2y= 4         <==== Multiply entire equation by -3 to get:

15x-6y = -12  

2x+3y= 6          <====  Multiply entire equation by 2 to get :

4x+6y = 12    Add the two underlined equations to eliminate 'y'

19x = 0     so x = 0

sub in x = 0 into any of the equations to find:  y = 2

(0,2)

To prove that if each of a, b, and c are relatively prime to n, then the product abc is also relatively prime to n, we can use the property that the greatest common divisor (gcd) of two numbers remains the same if one of the numbers is multiplied by a constant.

Let's assume that gcd(a, n) = gcd(b, n) = gcd(c, n) = 1. This means that a, b, and c are all relatively prime to n.
We want to show that gcd(abc, n) = 1.
To do this, we can use the fact that gcd(a, n) = gcd(b, n) = gcd(c, n) = 1. This implies that there exist integers x, y, and z such that ax + ny = 1, bx + ny = 1, and cx + nz = 1.

Now, let's multiply these equations together:
(ax + ny)(bx + ny)(cx + nz) = 1 * 1 * 1

Expanding this expression, we get:
abxcx + abxnz + axnycx + axnynz + nybxcx + nybxnz + nyanycx + nyanynz = 1

Simplifying further, we obtain:
abc(xcx) + ab(nzx) + a(nycx) + a(nynz) + b(nycx) + b(nynz) + n(ybxcx) + n(ybxnz) + n(yanycx) + n(yanynz) = 1

Notice that each term in this equation has at least one factor of n. Therefore, we can rewrite it as:
n[abc(xcx) + ab(nzx) + a(nycx) + a(nynz) + b(nycx) + b(nynz) + ybxcx + ybxnz + yanycx + yanynz] + abc(xcx) + ab(nzx) + a(nycx) + a(nynz) + b(nycx) + b(nynz) + ybxcx + ybxnz + yanycx + yanynz = 1

The left side of the equation contains n as a factor, so the right side must also contain n as a factor. However, the right side is equal to 1, which is not divisible by n. Therefore, the only possibility is that the coefficient of n on the left side is 0:
abc(xcx) + ab(nzx) + a(nycx) + a(nynz) + b(nycx) + b(nynz) + ybxcx + ybxnz + yanycx + yanynz = 0

This implies that abc is relatively prime to n, as gcd(abc, n) = 1.
Therefore, we have proven that if gcd(a, n) = gcd(b, n) = gcd(c, n) = 1, then gcd(abc, n) = 1.

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An integer n to be great if n² – 1 is a multiple of 3 because (N + 3)² - 1 = 3m. Since 8 and 3 are relatively prime, it follows that 3 | a.

From the definition, we know that N² - 1 is divisible by because  

We can write this as:

N² - 1 = 3k, where k is some integer.

Adding 6k + 9 to both sides, we have:

N² + 6k + 9

= 3k + 9

= 3(k + 3)

= 3m(m is some integer)

This simplifies to:

(N + 3)² - 1 = 3m, so we can conclude that N + 3 is also great.

2. We want to prove that 3 | 8a if and only if 3 | a.

Let's first assume that 3 | a.

This means that a = 3k for some integer k.

We can then write 8a as:

8a

= 8(3k)

= 24k

= 3(8k), which shows that 3 | 8a.

Now assume that 3 | 8a.

This means that 8a = 3k for some integer k. Since 8 and 3 are relatively prime, it follows that 3 | a.

3. We want to prove that if n is even, then n can be written as either n = 4k or n = 4k + 2, for some integer k.

We can consider two cases:

Case 1: n is divisible by 4If n is divisible by 4, then n can be written as n = 4k for some integer k.

Case 2: n is not divisible by 4If n is not divisible by 4, then we know that n has a remainder of 2 when divided by 4.

This means that we can write n as: n = 4k + 2, where k is some integer.

Together, these two cases show that if n is even, then either

n = 4k or

n = 4k + 2 for some integer k.

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The numerical value of x in the measure of the vertical angles is 16.

Vertical angles are simply angles which are opposite of one another when two lines cross.

Vertical angles have the same angle measure, hence, they are congruent.

From the diagram, as the two lines crosses, the two angles are opposite of each other, hence the angles are vertical angles.

Angle 1 = 65 degrees

Angle 2 = ( 4x + 1 ) degrees

Since vertical angles are congruent.

Angle 1 = Angle 2

Hence:

65 = ( 4x + 1 )

We can now solve for x:

65 = 4x + 1

Subtract 1 from both sides:

65 - 1 = 4x + 1 - 1

64 = 4x

x = 64/4

x = 16

Therefore, the value of x is 16.

Option D) 16 is the correct answer.

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To calculate the probability that an adult over 40 years of age is diagnosed with the disease, we need to consider the given probabilities: the probability of selecting an adult over 40 with the disease,

the probability of correctly diagnosing a person with the disease, and the probability of incorrectly diagnosing a person without the disease. The probability can be calculated using the formula for conditional probability.

Let's denote the probability of selecting an adult over 40 with the disease as P(D), the probability of correctly diagnosing a person with the disease as P(C|D), and the probability of incorrectly diagnosing a person without the disease as having the disease as P(I|¬D).

The probability that an adult over 40 years of age is diagnosed with the disease can be calculated using the formula for conditional probability:

P(D|C) = (P(C|D) * P(D)) / (P(C|D) * P(D) + P(C|¬D) * P(¬D))

Given the probabilities:

P(D) = probability of selecting an adult over 40 with the disease,

P(C|D) = probability of correctly diagnosing a person with the disease,

P(I|¬D) = probability of incorrectly diagnosing a person without the disease as having the disease,

P(¬D) = probability of selecting an adult over 40 without the disease,

we can substitute these values into the formula to calculate the probability P(D|C).

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The rate of change for the given linear function on the coordinate plane is 5.

To find the rate of change of a linear function, we can use the formula:

Rate of change = (change in y-coordinates)/(change in x-coordinates).

Given the points (1, -1) and (2, 4), we can calculate the change in y-coordinates as 4 - (-1) = 5, and the change in x-coordinates as 2 - 1 = 1.

Substituting these values into the formula, we have:

Rate of change = 5/1 = 5.

Therefore, the rate of change for the given linear function is 5.

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The polynomial division of (x^3 - 13x - 12) divided by (x - 4) results in a quotient of x^2 + 4x + 3 and a remainder of 0.

To perform polynomial division, we divide the given polynomial (x^3 - 13x - 12) by the divisor (x - 4). We start by dividing the highest degree term of the dividend (x^3) by the highest degree term of the divisor (x). This gives us x^2 as the first term of the quotient.

Next, we multiply the divisor (x - 4) by the first term of the quotient (x^2) and subtract the result from the dividend (x^3 - 13x - 12). This step cancels out the x^3 term and brings down the next term (-4x^2).

We repeat the process by dividing the highest degree term of the remaining polynomial (-4x^2) by the highest degree term of the divisor (x). This gives us -4x as the second term of the quotient.

We continue the steps of multiplication, subtraction, and division until we have no more terms left in the dividend. In this case, after further calculations, we obtain a final quotient of x^2 + 4x + 3 with a remainder of 0.

Therefore, the polynomial division of (x^3 - 13x - 12) by (x - 4) results in a quotient of x^2 + 4x + 3 and a remainder of 0.

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We have shown that the left-hand side (2+2×3+3×4+⋯+(n−1)×n) and the right-hand side (2(n+1 3)) represent the same counting problem, confirming the combinatorial proof of the identity.

To provide a combinatorial proof of the identity 2+2×3+3×4+⋯+(n−1)×n=2(n+1 3), we will classify sets of three numbers from the integer interval [0, N] by their maximum element.

Consider a set S with three distinct elements from the interval [0, N]. We can classify these sets based on their maximum element:

Case 1: The maximum element is N

In this case, the maximum element is fixed, and the other two elements can be any two distinct numbers from the interval [0, N-1]. The number of such sets is given by (N-1 2), which represents choosing 2 elements from N-1.

Case 2: The maximum element is N-1

In this case, the maximum element is fixed, and the other two elements can be any two distinct numbers from the interval [0, N-2]. The number of such sets is given by (N-2 2), which represents choosing 2 elements from N-2.

Case 3: The maximum element is N-2

Following the same logic as before, the number of sets in this case is given by (N-3 2).

We can continue this classification up to the maximum element being 2, where the number of sets is given by (2 2).

Now, if we sum up the number of sets in each case, we obtain:

(N-1 2) + (N-2 2) + (N-3 2) + ⋯ + (2 2)

This sum represents choosing 2 elements from each of the numbers N-1, N-2, N-3, ..., 2, which is exactly (N+1 3).

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The average angular speed of the hand is ω = 1800 / t rad/s and 103140 / t degrees/s and the average linear speed of the hand is 5D / t m/s.  The answers to A and B are not the same as they refer to different quantities with different units and different values.

A) To find the average angular speed of the hand, we need to use the formula:

angular speed (ω) = (angular displacement (θ) /time taken(t))

= 5 × 360 / t

Here, t is the time for 5 rotations

So, average angular speed of the hand is ω = 1800 / trad/s

To convert this into degrees/s, we can use the conversion:

1 rad/s = 57.3 degrees/s

Therefore, ω in degrees/s = (ω in rad/s) × 57.3

= (1800 / t) × 57.3

= 103140 / t degrees/s

B) To find the average linear speed of the hand, we need to use the formula:linear speed (v) = distance (d) /time taken(t)

Here, the distance of the hand is the length of the arm.

Distance from shoulder to middle of hand = D

Similarly, the time taken to complete 5 rotations is t

Thus, the total distance covered by the hand in 5 rotations is D × 5

Therefore, average linear speed of the hand = (D × 5) / t

= 5D / t

= 5 × distance of hand / time for 5 rotations

C) No, the answers to A and B are not the same. This is because angular speed and linear speed are different quantities. Angular speed refers to the rate of change of angular displacement with respect to time whereas linear speed refers to the rate of change of linear displacement with respect to time. Therefore, they have different units and different values.

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a)  Contingency tables: Total   100.00% 100.00%  100.00%

b) Based on the column percentages, we can see that among those who felt overloaded with too much information, a higher percentage were female (88.08%) compared to male (58.65%).

a. Contingency tables:

Total Percentages:

         Male   Female    Total

Yes      28.55%  45.20%   73.82%

No       20.13%   6.12%   26.18%

Total    48.68%  51.32%  100.00%

Row Percentages:

          Male   Female    Total

Yes       38.70%  61.30%  100.00%

No        76.69%  23.31%  100.00%

Total     48.68%  51.32%  100.00%

Column Percentages:

         Male   Female    Total

Yes      58.65%  88.08%   73.82%

No       41.35%  11.92%   26.18%

Total   100.00% 100.00%  100.00%

b. Based on the total percentages, we can see that overall, 73.82% of the survey respondents felt overloaded with too much information.

Based on the row percentages, we can see that a higher percentage of females (61.30%) felt overloaded with too much information compared to males (38.70%).

Based on the column percentages, we can see that among those who felt overloaded with too much information, a higher percentage were female (88.08%) compared to male (58.65%).

Therefore, we can conclude that there is a gender difference in terms of feeling overloaded with too much information, with a higher percentage of females reporting information overload compared to males.

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The value of inverse function [tex]f^{(-1)}(5)[/tex] is 2 when function f(x)=√x+2+3.

To find [tex]f^{(-1)}(5)[/tex], we need to determine the value of x that satisfies f(x) = 5.

Given that f(x) = √(x+2) + 3, we can set √(x+2) + 3 equal to 5:

√(x+2) + 3 = 5

Subtracting 3 from both sides:

√(x+2) = 2

Now, let's square both sides to eliminate the square root:

(x+2) = 4

Subtracting 2 from both sides:

x = 2

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The term that describes the distribution of the given graph is "skewed left."

Based on the given dot plot, the distribution of the graph can be described as skewed left.

A skewed left distribution, also known as a negatively skewed distribution, is characterized by a longer tail on the left side of the graph.

In this case, the values 1, 1, 1, 2, and 3 are clustered on the left side, indicating a concentration of lower values.

The distribution gradually becomes less dense as the values increase.

The term "skewed left" accurately describes the shape of the graph in this dot plot.

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Answer:

AM: 8.6 units

BM: 8.6 units

M is the center

Step-by-step explanation:

We are given that the diameter of a circle is AB, where point A is at (-1, -9) and point B is (-11, 5).

We know that point M, which is at (-6, -2) is on AB. We want to know if it is the center of the circle.

If it is the center, then it means that the distance (measure) of AM is the same as the distance (measure) of BM.

Recall that the distance formula is [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex], where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points.

The endpoints are point A and point M. We can label the values of the points to get:

[tex]x_1=-1\\y_1=-9\\x_2=-6\\y_2=-2[/tex]

Now, plug them into the formula.

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]d=\sqrt{(-6--1)^2+(-2--9)^2}[/tex]

[tex]d=\sqrt{(-6+1)^2+(-2+9)^2}[/tex]

[tex]d=\sqrt{(-5)^2+(7)^2}[/tex]

[tex]d=\sqrt{25+49}[/tex]

[tex]d=\sqrt{74}[/tex] ≈ 8.6 units

The endpoints are point B and point M. We can label the values and get:

[tex]x_1=-11\\y_1=5\\x_2=-6\\y_2=-2[/tex]

Now, plug them into the formula.

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]d=\sqrt{(-6--11)^2+(-2-5)^2}[/tex]

[tex]d=\sqrt{(-6+11)^2+(-2-5)^2}[/tex]

[tex]d=\sqrt{(5)^2+(-7)^2}[/tex]

[tex]d=\sqrt{25+49}[/tex]

[tex]d=\sqrt{74}[/tex] ≈ 8.6 units.

Since the length of AM an BM are the same, M is the center of the circle.

To solve the problem, you will follow the problem-solving process, which consists of four steps:
1. What do I have to do?
2. Devise a plan - what is it?
3. Carry out the plan (show work)
4. Look back and check: how do I know my answer is correct?

Step 1: What do I have to do?
You need to choose any number between 32 and 56, add 20 to it, subtract 17, and then subtract your original number.

Step 2: Devise a plan - what is it?
Let's say we choose the number 40 as an example. We'll follow the steps with this number and then try it with two other numbers.

Step 3: Carry out the plan (show work)
- Choose the number: 40
- Add 20: 40 + 20 = 60
- Subtract 17: 60 - 17 = 43
- Subtract the original number: 43 - 40 = 3

So, the result with the number 40 is 3.

Step 4: Look back and check: how do I know my answer is correct?
To check if our answer is correct, we can go through the steps again with another number and see if we get the same result.

Let's try it with the number 50:
- Choose the number: 50
- Add 20: 50 + 20 = 70
- Subtract 17: 70 - 17 = 53
- Subtract the original number: 53 - 50 = 3

The result with the number 50 is also 3, which matches our previous answer.

Now, let's try it with the number 35:
- Choose the number: 35
- Add 20: 35 + 20 = 55
- Subtract 17: 55 - 17 = 38
- Subtract the original number: 38 - 35 = 3

The result with the number 35 is also 3.

Therefore, we can conclude that regardless of the number chosen between 32 and 56, the result will always be 3.

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Answer: The original price is $460.

Step-by-step explanation: Since the sofa is sold at a 68% discount (0.68) from the original price, the sofa during the sale cost 32% (0.32) of the original price. Therefore, $147.20 =  (0.32)* original price and dividing both sides by 0.32, the original price is $460.

The statement "If 0 is the only eigenvalue of A ∈ M₁x3(C), then A = 0" is false.

To demonstrate this, we can provide a counter-example. Consider the following matrix:

A = [0 0 0]

[0 0 0]

In this case, the only eigenvalue of A is 0. However, A is not equal to the zero matrix. Therefore, the statement is false.

The matrix A can have all zero entries, except for the possibility of having non-zero entries in the last row. In such cases, the matrix A will still have 0 as the only eigenvalue, but it won't be equal to the zero matrix. Hence, the statement is not true in general.

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